Question

one number is 7 more than other and its square is 77 more than the square of the smaller number what are the numbers? answer should come 4..... Give the right answer otherwise I will report​

Answer 1

Answer:

let one no. be x and another no. be x+7

the according to question,

77+x^2=( x+7)^2

77+x^2= x^2 + 49 + 14x

14x= 77-49

14x = 28

x=2

Answer 2

Answer:

2 and 9

Step-by-step explanation:

let the numbers be x and x+7

(x+7)^2=x^2+77 (given)

so,x^2+ 14x +49=x^2+77

14x=28

x=2

so,numbers are 2 and 9