one number is 7 times another if their difference is 18 find the number
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Answered by
85
Let the number be, 'n'
So, the other number is (n×7)
= 7n
According to the problem,
7n-n = 18
⇒ 6n = 18
⇒ n = 18/6
⇒ n = 3
So, one of the number is 3.
∴ The other number is (3×7)
= 21
So, the other number is 21.
Check whether the calculation is correct or not:
One of the number = 3
The other number is 7 times of 3 = (3×7)
= 21
The difference between the numbers is =(21-3)
= 18
Hence, the numbers are 3 and 21.
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4
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