Question

One number is 8 times another number. The numbers are both positive and have a difference of 70. Find the numbers. Which of the following equations could be used to solve the problem?

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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$<u>Your Question -</u>$

One number is 8 times another number. The numbers are both positive and have a difference of 70. Find the numbers.

$<u>Solution -</u>$

Let the first number be 'x'.
Then, second number = 8 × x = 8x


So, their difference
= second number - first number
= 8x - x


But, their difference is 70. (as given in the question)

=> 8x - x = 70

=> 7x = 70

=> x = 70/7

=> x = 10

$<marquee>Hence, the first number = x = 10$

$And, second number = 8x = 8 × 10 = 80</marquee>$
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Thank you. ;-)