Question

One number is 9 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 782 ​, find the numbers. The three numbers are? [_]

Answer 1

Step-by-step explanation:

$\large\underline{\underline{\sf{\color{orange}{Answer :-}}}}$

$\displaystyle \sf \longrightarrow \1st number = x$

$\displaystyle \sf \longrightarrow \2nd number = 9x$

$\displaystyle \sf \longrightarrow \3rd number = x + 100$

$\tt : \implies \: x + 9x + x + 100 = 782 \\ \\ \tt : \implies \: 11x \: = \: 782 - 100 \: \: \: \: \: \: \: \: \: \: \\ \\ \tt : \implies 11x \: = \: 682 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \tt : \implies \: x \: = \: 62 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \bigstar \sf \: \: first \: number \: = \: 62 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bigstar \sf \: \: second \: number \: = \: 9 \times 62 = 558 \\ \\ \bigstar \sf \: \: third \: number = \: 62 + 100 = 162$