One number is chosen from numbers 1 to 200. Find the probability that it is divisible by 4 and 6 both.
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The numbers which are divisible by both 4 and 6 are :-
12,24 , 36 ..... 192 which forms an A.P. with common difference 12 and first term 12.
So 192= 12+(n-1) (12)
or n = 16 i.e. there are only 16 terms in between 1 to 200.
Probability= 16/200 = 2/25
12,24 , 36 ..... 192 which forms an A.P. with common difference 12 and first term 12.
So 192= 12+(n-1) (12)
or n = 16 i.e. there are only 16 terms in between 1 to 200.
Probability= 16/200 = 2/25
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