Question

one number is five times other number. if large number is subtracted from 60,the result is five less than smaller number subtracted from 45​

Answer 1

$let \: the \: first \: number \: be \: \: a$

$second \: number \: = 3a$

$60 - 3a = (55 - a) - 5$

$60 - 3a = 50 - a$

$2a = 10$

$a = 5$

$first \: number \: = 5$

$second \: number \: = 15$

Answer 2

Answer

AnswerLet the first number be 'a'

AnswerLet the first number be 'a'Second number = 3a.

AnswerLet the first number be 'a'Second number = 3a.According to question

AnswerLet the first number be 'a'Second number = 3a.According to question60−3a=(55−a)−5

AnswerLet the first number be 'a'Second number = 3a.According to question60−3a=(55−a)−560−3a=50−a.

AnswerLet the first number be 'a'Second number = 3a.According to question60−3a=(55−a)−560−3a=50−a.2a=10.

AnswerLet the first number be 'a'Second number = 3a.According to question60−3a=(55−a)−560−3a=50−a.2a=10.a=5

AnswerLet the first number be 'a'Second number = 3a.According to question60−3a=(55−a)−560−3a=50−a.2a=10.a=5∴ First number = 5

AnswerLet the first number be 'a'Second number = 3a.According to question60−3a=(55−a)−560−3a=50−a.2a=10.a=5∴ First number = 5second number = 15