Question

One number is four less than three times another. If their sum is increased by six , then the result is thirty. Find the numbers
Guys I want the answer now please I am having a test tomorrow and this is important​

Answer 1

Answer:

7, 17

Step-by-step explanation:

Let, one number be 'x'.

The other = 3x - 4

According to the problem,

$\implies$ (3x - 4) + x + 6 = 30

$\implies$ 4x + 2 = 30

$\implies$ 4x = 28

$\implies$ x = 28/4

$\implies$ x = 7

So, if one number is 7, the other

= 3x - 4

= 3(7) - 4

= 21 - 4

= 17

Therefore, the two numbers are 7 and 17.

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Answer 2

Given :-

• One number is four less than three times another. If their sum is increased by six , then the result is thirty.

To find :-

• Number

Solution :-

Let the first number be x then second number be (3x - 4)

According to the question

➭ [x + (3x - 4)] + 6 = 30

➭ [x + 3x - 4] + 6 = 30

➭ 4x - 4 + 6 = 30

➭ 4x + 2 = 30

➭ 4x = 30 - 2

➭ 4x = 28

➭ x = 28/4 = 7

Hence,

• First number = x = 7
• Second number = (3x - 4) = (3*7 - 4) = 17