one number is greater than
twice the other by 5. The sum
of these numbers is 23 . Find
the numbers.
Answers
Answered by
4
Let one number be x
So by the condition,other number is 2x+5
Sum of the numbers=23
X+2x+5=23
3x+5=23
3x=23-5
3x=18
X=18/3
X=6
So the first number,x=6 and the other number,2x+5=2*6+5
=12+5=17
So by the condition,other number is 2x+5
Sum of the numbers=23
X+2x+5=23
3x+5=23
3x=23-5
3x=18
X=18/3
X=6
So the first number,x=6 and the other number,2x+5=2*6+5
=12+5=17
Answered by
4
Answer:
Step-by-step explanation:
Let the first no. =x
the second no.=y
A/Q
x=2y+5. (when x is greater than y)
x-2y=5. (1)
again,
x+y=23. (2)
From (1) ×1+ (2)×2
x-2y=5
2x+2y=46
Add,
3x=51
x=51÷3
x=17
Putting value of (x) on (1) equation
x-2y=5
17-2y =5
-2y=5-17
-y=-12÷2
-y=-6
y= 6
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