Question

one number is randomly selected from the natural number 1 to 100. Find the probability that the number selected is either a single digit number or a perfect square.​

Answer 1

Answer:

p will be 19 /100 because 10 are perfect square and 9 are single digit no

Answer 2

Answer:

it is given that the number is selected here are 1 to 100 .

• so the total outcomes will be 100

Let us assume that the event A is for selecting number which is single digit number:-

• we know that there are 9 single digit number from 1 to 100.

So, probability of getting single digit number =

$\frac{9}{100}$

Now,

let asume that event B is for selecting perfect square =

$\frac{10}{100}$

Here, (A n B)= {1, 4, 9 } =

$\frac{3}{100}$

• P(A u B ) = P(A) + P( B) - P(A n B)

• $\frac{9}{100} + \frac{10}{100} - \frac{3}{100}$

• $\frac{9 + 10 - 3}{100}$

• $\frac{16}{100}$

• $\frac{4}{25}$

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