Question

one number is selected at random from first 100 natural number. find the probablitiy of getting perfect square number​

Answer 1

Answer: 24/25

Step-by-step explanation:

Total Numbers =1,2...100

=100

Perfect Squares

=1

2

,2

2

,3

2

...10

2

=1,4,9...100

=10 numbers

∴ Pralal =

100

10

=

10

1

Perfect Cube =1

3

,2

3

,3

3

...

=1,8,27,64

=4

∴ P (Not Perfect cube) =1−

100

4

=

25

24

Answer 2

Answer:

Step-by-step explanation:

n(S)=100

i)Let A be the event of getting a perfect square

A={1, 4, 9, 16, 25, 36, 49, 64, 81, 100 }

n(A)=10

p(A)=n(A)/n(S)

=10/100

=1/10

ii)Let B be the event of getting not a perfect cube

perfect cubes={1,8,27,64}

so,n(B)=100-4

=96

p(B)=n(B)/n(S)

=96/100

=48/50

=24/25