Question

one number is seven times another . if their difference is 18 . find the number
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Answer 1

Answer:

1st number = 21,   2nd number = 3

Step-by-step explanation:

Let the 1st number be x, and 2nd number be y.

Given, x = 7y  => x - 7y = 0______(1st eqtn)

          x - y = 18____(2nd eqtn)

Subtract 2nd eqtn from 1st eqtn.

       -6y = -18

        6y = 18

          y = 3

Put y = 3 in 2nd eqtn.

         x - 3 = 18

         x = 18 + 3

         x = 21

Hope you find my answer helpful....

Answer 2

ɢɪᴠᴇɴ :

• one number is seven times the other.
• Their difference is 18.

ᴛᴏ ғɪɴᴅ :

• Find the number.

sᴏʟᴜᴛɪᴏɴ :

Here, we are given with statement only and we need to make a linear equation out of it, and then solve the problem. First we will take the no: as x and then second as 7x, then by transpose method, we will solve it further.

sᴏ -

Let the number be termed as x

One is seven times the other number = 7x

Difference is of 18

ᴏɴ sᴜʙsᴛɪᴛᴜᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇs :

⟶ 7x - x = 18

⟶ 6x = 18

$⟶ x = \sf\cancel\dfrac{18}{6}$

⟶ x = 3

ɴᴏᴡ :

• First number = 3

• Second number = 7x = 7 × 3 = 21

ᴠᴇʀɪғɪᴄᴀᴛɪᴏɴ :

21 - 3 = 18

18 = 18

therefore∴

The first and second number are 3 and 21

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