Question

One number is seven times another, If their difference is 18, find the numbers. ​

Answer 1

Answer:

Let the number be, 'n'

So, the other number is (n×7)

                                     = 7n

According to the problem,

7n-n = 18

⇒ 6n = 18

⇒ n = 18/6

⇒ n = 3

So, one of the number is 3.

∴ The other number is (3×7)

                                    = 21

So, the other number is 21.

Check whether the calculation is correct or not:

One of the number = 3

The other number is 7 times of 3 = (3×7)

                                                      = 21

The difference between the numbers is =(21-3)

                                                                 = 18

Hence, the numbers are 3 and 21.

Step-by-step explanation:

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