Math, asked by gupteshwarsaw15, 1 year ago

One number is three times the another number. If 15 is added to both numbers, then one of the new numbers become twice that of the other new number . Find the numbers

Answers

Answered by Darvince
63

Answer:

The numbers are 15 and 45.

Step-by-step explanation:

Gívєn -

One Number is = Thrice the another

When 15 is added to both the numbers, then one of the new numbers become twice that of the other new number

Tσ fínd -

The Numbers

Sσlutíσn -

Let the numbers be as -

  • One Number as x
  • Second Number as 3x

\rule{300}{1.5}

When 15 is added to both -

  • (x + 15)
  • (3x + 15)

\rule{300}{1.5}

According to the Question -

The new numbers formed after adding 15, one of the new numbers become twice that of the other new number.

\sf{\implies} \: 2(x + 15) = (3x + 15)

\sf{\implies} \: 2x + 30= 3x + 15

\sf{\implies} \: 2x  - 3x=15 - 30

\sf{\implies} \:  \cancel-x=\cancel-15

One Number = 15

\rule{300}{1.5}

Second Number =

\sf{\implies} \: 3(15)

\sf{\implies} \: 45

Second Number = 45

\therefore The numbers are 15 and 45.

Answered by Blaezii
61

Answer :

Required Numbers are 45 and 15.

Step-by-step explanation :

Gɪveη that :  

When 15 is added to both the numbers, then one of the new numbers become twice that of the other new number.

One Number = Thrice the another.

To Find :

The Numbers.

Solution :

\bigstar\;\textbf{\underline{\underline{Consider as -}}}}

One number as - x

Second Number as - y

According to your Question,

⇒ x = 3y      .............Eq(i)

As Given; 15 is added to both Numbers by which it becomes,

⇒ x + 15 & y + 15.

⇒ (x + 15) = 2(y + 15)              ............Eq(ii).

Now, We have,

⇒ x = 3y   .............Eq(i)

⇒ (x + 15) = 2(y + 15)     ............Eq(ii)

So,

Putting value of Eq(i) in Eq(ii),

⇒ (x + 15) = 2(y + 15)        

Using the value of x here,

⇒ (3y + 15) = 2(y + 15)

⇒ 3y + 15 = 2y + 30

Subtraction of 15 from both sides,

⇒ 3y + 15 -15 = 2y + 30 -15

⇒ 3y = 2y + 15

Subtraction of 2y from both sides,

⇒ 3y - 2y = 2y + 15 -2y

⇒ y = 15

The value of y = 15.

Putting value of y in Eq(i),

⇒ x = 3(15)

⇒ x = 45

Therefore,

The value of y = 15 and value of x = 45

Hence, the two Numbers are 45 and 15

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