One number is three times the another number. If 15 is added to both numbers, then one of the new numbers become twice that of the other new number . Find the numbers
Answers
Answer:
The numbers are 15 and 45.
Step-by-step explanation:
Gívєn -
One Number is = Thrice the another
When 15 is added to both the numbers, then one of the new numbers become twice that of the other new number
Tσ fínd -
The Numbers
Sσlutíσn -
Let the numbers be as -
- One Number as x
- Second Number as 3x
When 15 is added to both -
- (x + 15)
- (3x + 15)
According to the Question -
The new numbers formed after adding 15, one of the new numbers become twice that of the other new number.
One Number = 15
Second Number =
Second Number = 45
The numbers are 15 and 45.
Answer :
Required Numbers are 45 and 15.
Step-by-step explanation :
Gɪveη that :
When 15 is added to both the numbers, then one of the new numbers become twice that of the other new number.
One Number = Thrice the another.
To Find :
The Numbers.
Solution :
One number as - x
Second Number as - y
According to your Question,
⇒ x = 3y .............Eq(i)
As Given; 15 is added to both Numbers by which it becomes,
⇒ x + 15 & y + 15.
⇒ (x + 15) = 2(y + 15) ............Eq(ii).
Now, We have,
⇒ x = 3y .............Eq(i)
⇒ (x + 15) = 2(y + 15) ............Eq(ii)
So,
Putting value of Eq(i) in Eq(ii),
⇒ (x + 15) = 2(y + 15)
Using the value of x here,
⇒ (3y + 15) = 2(y + 15)
⇒ 3y + 15 = 2y + 30
Subtraction of 15 from both sides,
⇒ 3y + 15 -15 = 2y + 30 -15
⇒ 3y = 2y + 15
Subtraction of 2y from both sides,
⇒ 3y - 2y = 2y + 15 -2y
⇒ y = 15
∴ The value of y = 15.
Putting value of y in Eq(i),
⇒ x = 3(15)
⇒ x = 45
Therefore,
The value of y = 15 and value of x = 45
Hence, the two Numbers are 45 and 15