Question

one numer is 4 less than the the three times another number .lf their sum is increased by 5the result is 25 .find both the numbers

Answer 1

let 2 numbers be x and y
y=3x-4
x + y + 5 = 25
x + 3x - 4 + 5 = 25
4x +1 = 25
4x = 24
x = 6, So one of the numbers is 6, now solve for y
y = 3x-4 = 3(6)-4 = 14 

Answer 2

Answer:

Step-by-step explanation:

Let one no. be x

Another no. = 3x -4

A/q

x + 3x -4 +5 = 25

4x + 1 =25

4x = 25 - 1

4x = 24

x = 24/4

x= 6

So, one no. = 6

Another =3x-4 = 3×6-4 =14