Question

one o box contain Ito 100 number cords It cond is drawn at random 1) a perfect square 2.a prime number 3.a two digit number 4. a multiple of 9
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Answer 1

Step-by-step explanation:

There are 100 cards in the box marked with number 1 to 100.

A card is drawn randomly from it.

∴ Number of possible outcomes = 100

(1) Let A be the event that the card bears an even prime number.

There is only 1 even prime number from 1 to 100, that is '2'.

∴ The number of outcomes favourable to A is 1.

∴P(A)=

100

1

=0.01

(2) Let B be the event that the card bears a number divisible by 7.

Numbers divisible by 7 from 1 to 100 are

7,14,21,28,35,42,56,63,70,77,84,91,98

There are 13 multiples of 7 from the numbers 1 to 100.

∴ The number of outcomes favourable to B is 13.

∴P(A)=

100

13

=0.13

(3) Let be the event that the card bears a number that has 9 at the unit place.

The numbers from 1 to 100 that have 9 at the units place are

9,19,29,39,49,59,69,79,89,99

There are 10 numbers that have 9 at the unit place.

∴ The number of outcomes favourable to C is 10.

∴P(A)=

100

10

=0.1