Question

One object of mass 1 kg was moving with a velocity of 36 km/h. Suddenly it

collides with another object of mass 1 kg and sticks together. What will be the velocity

of that combined object​

Answer 1

Answer:

Mass of the object, m1 = 1 kg

Velocity of the object before collision, v1 = 10 m/s

Mass of the stationary wooden block, m2 = 5 kg

Velocity of the wooden block before collision, v2 = 0 m/s

ˆ´ Total momentum before collision = m1 v1 + m2 v2

= 1 (10) + 5 (0) = 10 kg m sˆ’1

It is given that after collision, the object and the wooden block stick together.

Total mass of the combined system = m1 + m2

Velocity of the combined object = v

According to the law of conservation of momentum:

Total momentum before collision = Total momentum after collision

m1 v1 + m2 v2 = (m1 + m2) v

1 (10) + 5 (0) = (1 + 5) v

v = 10 / 6

= 5 / 3

The total momentum after collision is also 10 kg m/s.

Total momentum just before the impact = 10 kg m sˆ’1

Total momentum just after the impact = (m1 + m2) v = 6 — 5 / 3 = 10 kg ms-1

Hence, velocity of the combined object after collision = 5 / 3 ms-1

Answer 2

Answer:

18 Km/h

Explanation:

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