Question

One of a angel of triangle is 50° and the other two Angeles is equal find the measure of each equal angel

Answer 1

Let equal angles be x
x+x+50=180
x=65
Therefore answer is 65°.

Answer 2

let the angles of triangle be angle A and angle B
A+B=180
50+B=180
B=180-50
B=130
hence each equal angle of triangle is 130
it was an isosceles triangle