Math, asked by varshakolgire2016, 10 hours ago

One of a pair of complementary angles, one is two - third of the other. Find the angles.

Answers

Answered by TwilightShine
18

Appropriate Question -

  • Of a pair of complementary angles, one is two-third of the other. Find the angles.

Answer -

  • The angles are 36° and 54°.

To find -

  • The angles.

Step-by-step explanation -

  • Let's form an equation using the information given to us and solve it to find out our answer!

Let -

  • One of the angles be "x".

Then -

  • The other angle will be "(2/3) x", as it is two-third of the first angle.

We know that -

 \bigstar \:  \underline{ \boxed{ \sf Complementary \:  angles \:  add  \: up \:  to \:  90^{\circ}}}

Therefore -

 \longmapsto \tt x +  \dfrac{2}{3} x = 90

 \longmapsto \tt x +  \dfrac{2x}{3}  = 90

 \longmapsto \tt \dfrac{(x \times 3) + (2x \times 1)}{3}  = 90

  \longmapsto \tt\dfrac{3x + 2x}{3}  = 90

 \longmapsto \tt \dfrac{5x}{3}  = 90

 \longmapsto\tt5x = 90 \times 3

 \longmapsto\tt5x = 270

 \longmapsto \tt x =   \cancel\dfrac{270}{5}

 \longmapsto \underline{\boxed{\tt x =  {54}^{ \circ}}}

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Hence, the complementary angles are -

 \Rightarrow\bf x =  {54}^{ \circ} .

 \Rightarrow\bf \dfrac{2}{3} x =  \dfrac{2}{3}  \times 54 =  {36}^{ \circ} .

________________________________


Eutuxia: Great answer! :D
TwilightShine: Thank you! :D
Answered by MathCracker
12

Question :-

One of a pair of complementary angles, one is two - third of the other. Find the angles.

Answer :-

  • The angles are 54° and 36°.

Step by step explanation :-

In the question we have said that the one pair of complementary angles one is two - third part of other. And we have asked to find the measure of angles.

Method of solving,

See here we have to assume the measures of angles and we use the property of complementary angles.

Assumption,

 \implies 1st angle be x.

 \implies 2nd angle be  \frac{2}{3} \\ x.

Complementary angles property,

 \implies Sum of two angles of complementary angles is 90°.

On using this property,

\rm:\longmapsto{x +  \frac{2}{3} x = 90 \degree} \\

Also can be written as,

\rm:\longmapsto{x +  \frac{2x}{3}  = 90 \degree} \\

Taking LCM,

\rm:\longmapsto{ \frac{3x + 2x}{3}  = 90 \degree} \\  \\ \rm:\longmapsto{5x = 90 \degree \times 3} \:  \:  \: \:   \\  \\ \rm:\longmapsto{5x = 270 \degree} \:  \:  \:  \:  \:  \:  \:   \: \:  \\  \\ \rm:\longmapsto{x = \cancel  \frac{270}{5} } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\ \rm:\longmapsto \red{x = 54 \degree} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

The angles are,

 \implies 1st angle = x = 54°

 \implies 2nd angle =  \frac{2}{3} \\ x

 \rm \implies{ \frac{2x}{3}  =  \frac{2(54)}{3} } \\  \\  \rm \implies{ \frac{108}{3}  =  \red {36 \degree }} \:  \:  \:

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