Question

one of a quadratic equation is 4-√7. find the equation​

Answer 1

Step-by-step explanation:

$\huge\bf{\mid{\overline{\underline{ANSWER:-}}\mid}}$

This roots occurs in pair

if one root is 4 - √7 then other root will be 4 + √7

Key idea

x² - (sum of roots)x + (product of roots) = 0

Let 4 - √7 be ¢ and 4 + √7 be ¥

¢ + ¥ = 4 - √7 + 4 + √7 = 8

¢ × ¥ = (4 - √7) × (4+√7) = 16 - 7 = 9

Now using our key idea

x² - (¢ + ¥)x + ¢¥ = 0

x² - 8x + 9 = 0

So your required equation is =>

x² - 8x +9 = 0

Extra info.

If quadratic equation is given..

¢ + ¥ = - b/a

¢ × ¥ = c/a

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