Question

one of a triangle is equal to the sum of the other two . if ratio of the other two angles is 7:8 find the angles of the triangle

Answer 1

Let one angle=x
Sum of other two angles also=x
ATQ,
x+x=180 [Angle sum property]
2x=180
x=90 degrees
Ratio=7:8
Let the angles be 7x and 8x
7x+8x=90
15x=90
x=6
Therefore the angles of triangle are 90, [6*7]=42, and [6*8]=48.

Answer 2

The first angle is equal to soon of other two.

Ratio between , second and third angle is 7:8

Let the angles be 7x and 8x.

So, first Angle = 7x+8x = 15x

According to Angle sum property of a triangle , sum of all 3 angles is 180→

7x+8x+15x = 180

or, 15x+15x = 180

or, 30x = 180

or, x = 180/30

or, x = 18/3

or, x = 6

Therefore angles are→

7x = 7(6) = 42

8x = 8(6) = 48

15x = 15(6) = 90

Answer→ The angles of Triangle are 42° , 48° and 90°
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