Question

One of its diagonals of a rhombus is 6cm. If its area is 24 sq cm. Then find the length of each side.​

Answer 1

Answer:

One of its diagonals of a rhombus is 6cm and

its area is 24 sq cm.

Then another diagonal of the Rhombus is,

$area = \frac{1}{2} \times d1 \times d2 \\ 24 = \frac{1}{2} \times 6 \times d2 \\ d2 = 8 \: cm$

The diagonal of Rhombus bisect each other at perpendicular.

So,

$\frac{1}{2} \times d1 = \frac{1}{2} \times 6 = 3 \: cm$

and,

$\frac{1}{2} \times d2 = \frac{1}{2} \times 8 = 4 \: cm$

Applying the property of Right Angle Theorem:

$side \: a = \sqrt{ {3}^{2} + {4}^{2} } = 5 \: cm$

The length of each side is 5 cm.

Answer 2

Answer:

here is your answer ..

Step-by-step explanation:

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