One of tge roots of Quadratic Equation 2x^2+kx-2=0 is -2,find k
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Answered by
184
Hi ,
It is given that -2 is a root of 2x² + kx - 2 = 0,
put x = -2 in the equation ,
2( - 2 )² + k ( -2 ) - 2 = 0
8 - 2k - 2 = 0
- 2k + 6 = 0
-2k = -6
k = ( -6 )/( -2 )
k = 3
I hope this helps you.
: )
It is given that -2 is a root of 2x² + kx - 2 = 0,
put x = -2 in the equation ,
2( - 2 )² + k ( -2 ) - 2 = 0
8 - 2k - 2 = 0
- 2k + 6 = 0
-2k = -6
k = ( -6 )/( -2 )
k = 3
I hope this helps you.
: )
abhi569:
Thank you soo much sir
(-:
Answered by
42
Hii friend,
P(X) = 2X²+KX-2 = 0
P(-2) = 2 × (-2)² + K × -2 -2
=> 2 × 4 -2K -2 =0
=> 8-2K -2 = 0
=> -2K = -6
=> K = -6/-2 = 3
Hence,
The Value of K is 3.
HOPE IT WILL HELP YOU..... :-)
P(X) = 2X²+KX-2 = 0
P(-2) = 2 × (-2)² + K × -2 -2
=> 2 × 4 -2K -2 =0
=> 8-2K -2 = 0
=> -2K = -6
=> K = -6/-2 = 3
Hence,
The Value of K is 3.
HOPE IT WILL HELP YOU..... :-)
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