One of the 2 digit number is 3 times the other digit if you interchange the digits of this two digit number and add the resulting number to the original number you get 88 what is original number
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Assume that ones digit is= x
then ten's digit will=3x
So number = 10×3x + x= 31x
After interchanging the digits:
ones digit will be= 3x
and tens digit will= x
So number = 10×x + 3x= 13x
According to the question:
31x + 13x = 88
44x = 88
x = 88/44 = 2
so ones digit is= 2 and tens digit will be= 3x= 3×2=6
And number is= 62
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