Question

one of the 2 digita of a 2 digit number is twice the other digit if you inter change the digit of the 2 digit number and add the resulting number to the orginal number you get 66 what os the original number
with steps calculate​

Answer 1

Answer:

Original number = 42

Step-by-step explanation:

Given:

• One digit of a two digit number is twice the other
• If the digits are interchanged and added to the original number we get 66

To Find:

• The original number

Solution:

Let the digit in the unit's place be x

Hence the digit in the ten's placewould be 2x

Therefore the original number would be,

Original number = 10 (2x) + x

Original number = 21x

Now if the digits are interchanged the reversed number is given by,

Reversed number = 10 x + 2x

Reversed number = 12x

By given,

Reversed number + Original number = 66

Hence,

12x + 21x = 66

33x = 66

x = 66/33

x = 2

Hence the digit in the unit's place is 2.

Now,

Digit in the ten's place = 2x = 2 × 2

Digit in the ten's place = 4

Therefore,

The number =  10 × 4  +2

The number = 42

Therefore the original number is 42.

Verification:

One digit = Two times the other digit

4 = 2 × 2

4 = 4

Reversed number  +Original number = 66

42 + 24 = 66

66 = 66

Hence verified.