Question

One of the angle of a parallelogram is twenty four degree less than double the smallest angle. The bigger angle of the parallelogram is ………………. . *

a.68°
b.102°
c.112°
d.176°

Answer 1

Answer:

x = Smaller angle  

2x-24 = Larger angle  

Sum of angles of a parallelogram = 360°

ATQ,

(x) + (x) + (2x-24) + (2x-24) = 360°

(2x) + (4x - 48) = 360°

6x - 48 = 360°

6x = 408

x = 68

∴, Larger angle= 2x - 24 = (2)(68) - 24 = 136 - 24 = c) 112