one of the angle of a triangle is 110° and the other two angles are equal. what is the measure of each of these equal angles
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Answered by
33
we know,
sum of all angles of triangle is 180 degree
let another two equal angle is x
now
x+x+110=180
=>2x+110=180
=> 2x=180-110=70
=> x=70/2=35
hence each equal angles are 35 degree
sum of all angles of triangle is 180 degree
let another two equal angle is x
now
x+x+110=180
=>2x+110=180
=> 2x=180-110=70
=> x=70/2=35
hence each equal angles are 35 degree
Answered by
29
One angle of the triangle = 110°
Let the other two angles each be x
Sum of all the angles of a triangle = 180°
x + x + 110 = 180
2x = 180 - 110
2x = 70
x = 35°
The other two angles are 35°, 35°.
Let the other two angles each be x
Sum of all the angles of a triangle = 180°
x + x + 110 = 180
2x = 180 - 110
2x = 70
x = 35°
The other two angles are 35°, 35°.
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