One of the angle of a triangle is 60°. Find the remaining two angles, if their difference is 50°.
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Let the angles of triangle be, 1, 2 , 3 .
1 = 60°
and,
2 - 3 = 50°
2 = 50° + 3 (i)
By ASP of Triangle,
1 + 2 + 3 = 180°
60° + 50° + 3 + 3 = 180°
2(3) = 180° - 110°
3 = 70°/2
3 = 35° 【3 = Angle 3】
Angle 2 = 50° + Angle 3 [ from (i) ]
Angle 2 = 50° + 35°
Angle 2 = 85°
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