Math, asked by sihhsjjs8946, 6 months ago

One of the angle of a triangle pqr is 80 degree and the other two Triangles are equal find the measure of each of the equal angle

Answers

Answered by ishakumari81788
2

Answer:

50° each

Step-by-step explanation:

Given= PQR= 80°

Let other two angles be x

therefore, x+x+80°=180°(Angle sum Property of triangle)

80°+2x=180°

2x=180°-80°

2x=100°

x=100°/2

therefore, x= 50°

Answered by yateesh56
1

Step-by-step explanation:

sum of all angles in a triangle is 180°

one Angle's measure is 80°

other 2 angles are equal

let 1 of the equal angles be x°

80°+x°+x°=180°

2x°=180°-80°

x°=100°/2

x°=50° is the measure of each of the equal angel

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