Math, asked by barsha734, 3 months ago

one of the angle of triangle is 74 degree
and the two two angles are equal find the measure of each of the equal angles​

Answers

Answered by shalin0012237
1

Answer:

53

Step-by-step explanation:

If two angles are equal, we will do =

x+x+74 = 180

2x = 180 - 74

2x = 106

x = 106/2

x = 53

Answered by Yuseong
53

Answer:

53°

Given:

• One of the angle of triangle = 74°

• Other two angles are equal.

To calculate:

• The measure of each of the equal angles.

Calculation:

Let the each of the two equal angles be x°.

As we know that,

⇒ Sum of angles of the triangle = 180°

According to the question,

⇒ First angle + Second angle + Third angle = 360°

⇒ 74° + x° + x° = 180°

⇒ 74° + 2x° = 180°

⇒ 2x° = 180° - 74°

⇒ 2x° = 106°

⇒ x° = 106°/2

x° = 5

Hence, the measure of each of the equal angles is 53°.

Verification:

⇒ Sum of angles of the triangle = 180°

LHS :

⇒ Sum of angles of the triangle

⇒ 74° + x° + x°

⇒ 74° + 53° + 53°

⇒180°

RHS:

⇒180°

Hence, verified!

More about triangles!

Angle sum property of a triangle :

Sum of interior angles of a triangle = 180°

Exterior angle property of a triangle :

Sum of two interior opposite angles = Exterior angle

Perimeter of triangle :

Sum of all sides

Area of triangle :

\sf { \dfrac{1}{2} \times Base \times Height }

Area of an equilateral triangle:

\sf { \dfrac{\sqrt{3}}{4} \times  {Side}^{2} }

Area of a triangle when its sides are given :

 \sf { \sqrt{s[ (s-a)(s-b)(s-c) ]} }

Where,

S= Semi-perimeter or  \sf {\dfrac{a+b+c}{2} }

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