One of the angles of a quadrilateral measures 108 degree and the remaining angles are equal.find the measure of each of the equal angles
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hey mates
here is the answer
as the question says !!!
= one angle measure=108
= and remaining angles are equal...
let all the remaining angles be =x
a/q
then
x+x+x+108=360(sum of the angles of a quadlaterals)
= 3x+108=360
= 3x=360-108
= 3x=252
= x=252÷3
= x=84
then all the three angle will be 84 degree
here is the answer
as the question says !!!
= one angle measure=108
= and remaining angles are equal...
let all the remaining angles be =x
a/q
then
x+x+x+108=360(sum of the angles of a quadlaterals)
= 3x+108=360
= 3x=360-108
= 3x=252
= x=252÷3
= x=84
then all the three angle will be 84 degree
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