Question

One of the angles of a triangle is 50º and the other two angles are equal. Find the measure

of each of the equal angles.​

Answer 1

Answer:

Suppose the angels be A,B,C

we know

In triangle

angA+angB+angC=180°

as B=C

50+2B=180°

2B=130°

B=65°,C=65°

Hence,angA=50°,angB=65°&angC=65°