One of the angles of a triangle is 55 degree find the othr two angles , if their difference is 35 degree
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X+(X+35°)+55° = 180°
2X+90° = 180°
2X = 180°–90° = 90°
X = 90°/2 = 45°
X + 35° = 45°+35° = 80°
2X+90° = 180°
2X = 180°–90° = 90°
X = 90°/2 = 45°
X + 35° = 45°+35° = 80°
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