one of the angles of a triangle is 58° and the other two angles are equal. find the measure of each of the equal angles.
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Answered by
1
let the angles be x
then,
58 + 2x =180(sum of all angles in a triangle is 180)
2x= 180-58=122
x=122÷2=61
then,
58 + 2x =180(sum of all angles in a triangle is 180)
2x= 180-58=122
x=122÷2=61
Gurpreetsingh56:
where r u from
Answered by
1
let angle a=58°
let angle b and c=x
by angle sum property
a + b + c = 180°
58°+ x + x = 180°
2x = 180°-58°
2x=122°
x=122°/2
x=61°
so angle a = b = 61°
let angle b and c=x
by angle sum property
a + b + c = 180°
58°+ x + x = 180°
2x = 180°-58°
2x=122°
x=122°/2
x=61°
so angle a = b = 61°
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