Question

One of the angles of a triangle
is 6o degree and the other two
are in the ratio 3:2 find these
angles​

Answer 1

Answer:

1 angle is 72°

2 angle is 48°

Step-by-step explanation:

let,

first angle be 3x

second angle be 2x

third angle = 60°

we know that sum of three angle is 180°

60° + 3x + 2x = 180°

60 + 5x = 180°

5x = 180° - 60°

5x = 120°

x = 120/5

x = 24°

first angle 3x = 3×24 = 72°

second angle 2x = 2×24 = 48°

Answer 2

Given that one of the angles of the given triangle is 60°.

Also given that the other two angles of the triangle are in the ratio 3:2.

Let one of the other two angles be 3x.

Therefore, the second one will be 2x.

We know that the sum of all the three angles of a triangle is equal to 180°

60° + 3x + 2x = 180°

5x = 180° – 60°

5x = 120°

x = 120°/5

x = 24°

3x=3 x 24=72°.

2x = 2 × 24=48°.