Question

One of the angles of a triangle is 75° find the remaining 2 angels if their difference is 35°

Answer 1

one angle is 75°
than the remaining two angle are 105°
if one angle is x°
than other is x°+35°
according to Q
x°+x°+35°=105°
2x°+35°=105°
x°=105°-35°/2
x°=35°
then remaining two angle are-
one is 35°
and other is 70°
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Answer 2

Given:
Angle 1 = 75°
Angle2 - Angle 3= 35°
Angle 3= 35+angle 2
Solution:
Angle 1+Angle 2 + Angle 3 = 180° [angle sum property]
75°+ angle 2 +angle 3 = 180
Angle 2+Angle 3= 105°
Angle 2 + 35+ angle2 =105
2×(angle 2)= 70
Angle2= 70/2=35°
Now, Angle 3= 35+35= 70°
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