Question

One of the angles of a triangle is 80 degrees and the other two angles are equal. Find the measure of each of the equal angles.

Answer 1

Let the two angles be equal to x. Since they are equal we assume both of them to be x.

So according to angle sum property of triangle, the sum of all the interior angles of a triangle sum up to 180°.

=> Angle 1 + Angle 2 + Angle 3 = 180°

=> x + x + 80° = 180°

=> 2x + 80° = 180°

=> 2x = 180° - 80°

=> 2x = 100°

=> x = 100° / 2

=> x = 50°

Hence the angle measure of the two equal angles are 50°.

Answer 2

For the given triangle, the measure of each of the equal angles is 50°.

Given,

One angle of a triangle = 80°.

The other two angles are equal.

To find,

The measure of each of the equal angles.

Solution,

Firstly, let each of the two equal angles measure x degrees.

We are given that one of the three angles of a triangle is 80°.

Now, we know that the sum of three angles of a triangle is equal to 180°.

So, for the given triangle, we can write,

80 + x + x = 180

Simplifying and rearranging the above equation, we get,

2x = 180 - 80

⇒ 2x = 100

$\implies x = \frac{100}{2}$

⇒ x = 50°.

⇒ the measure of each of the equal angles = 50°.

Therefore, for the given triangle, the measure of each of the equal angles is 50°.

#SPJ3