Question

One of the angles of a triangle is 80° and the other two angles are equal. Find the measure of each of these equal angles

50°

45°

115°

60°
plz ans​

Answer 1

Answer:

50°

Explanation:

80+x+x=180°

80+2x=180°

2x=180°-80°

2x=100

X=80°

Answer 2

Let the two same angles in triangle be x.

Now, As we know the sum of internal angles of a triangle is 180. so,

80^0+x+x=180^0

2x=180^0-80^0

2x=100^0

x=50^0.

Hence both other angles are 50^0 each.