Question

one of the angles of a triangle is equal to the sum of the other two angles. if the ratio of the other angle is 8:10. find the angle of the length. ​

Answer 1

solution

Given that one angle of a triangle is equal to the sum of other two. if the ratio of the other two angles is 7:8.

we have to find the angles of the triangle.

Let the angles of triangle be x, y and z

As one angle of a triangle is equal to the sum of other two

x=y+z

also the ratio of the other two angles is 7:8.

y:z=7:8

Let y be 7a and z be 8a

∴ x=7a+8a=15a

By angle sum property of triangle

x+y+z=180°

⇒ 15a+7a+8a=180°

⇒ 30a=180° ⇒ a=6

Hence, angles are

x=15a=15(6)=90°

y=7a=7(6)=42°

z=7a=8(6)=48°

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Answer 2

Answer:

Step-by-step explanation:

Lets take 8 as 8x and 10 as 10x

8x+10x= 18x

As mentioned in the q than sum of the 1 and 2 angle is equal to 3 angle

So, now we know than 1 angle=8x:2 angle=10x and 3 angle = 18x

Now as we also know that some of the angles is equal to 180 degree

So, 8x+10x+18x=180degree

18x+18x= 180 degree

36x=180

x= 180/36

x=5 degree

3 angle = 18*5=90degree

2angle=10*5=50 degree

1 angle = 8*5=40 degree

Hope it helps u.