Question

One of the angles of a triangle is twice the other angle.If the third angle is 100, find the angles.​

Answer 1

THERE ARE THREE ANGLES IN A TRIANGLE

A T.Q

one of the angle is twice than the other

LET THE SECOND ANGLE BE X

so the first angle would be 2x

third angle is 100 as given

A.T.E

100+2X+X=180

100+3X=180

3X=180-100

3X=80

X=

$\frac{80}{3}$

Answer 2

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