one of the angles of triangle is 75° , find the remaining two angles if their difference is 35°.
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Answered by
168
Let one angle be x and another be y
x+y=180°-75°=105°-eq i
given,
x-y=35°-eq ii
on substracting eq ii from eq i
2y=70°
y=70°/2
y=35°
x=70°
x+y=180°-75°=105°-eq i
given,
x-y=35°-eq ii
on substracting eq ii from eq i
2y=70°
y=70°/2
y=35°
x=70°
Answered by
104
hope this will help you..
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