Question

One of the diagonal of the rhombus is double the other diagonal its area is 25 sq.Cm the sum of diagonal is

Answer 1

Answer:

sum of diagonal is 15**************

Answer 2

The sum of diagonals is 61.23 cm

Step-by-step explanation:

Area of rhombus = $\frac{pq}{2}$

Where p and q are the diagonals

Let the one diagonal of given rhombus be x

We are given that One of the diagonal of the rhombus is double the other diagonal

So, Another diagonal = 2x

So, Area of rhombus = $\frac{x \times 2x}{2}=\frac{3x^2}{2}$

Area of rhombus = 25 sq,cm,

So, $\frac{3x^2}{2}=25\\x^2=\frac{25 \times 50}{3}\\x=20.41$

Another diagonal = 2x = 2(20.41)=40.82  cm

Sum of diagonals = 20.41 cm + 40 .82 cm = 61.23 cm

Hence The sum of diagonals is 61.23 cm

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