Question

One of the diagonals of a quadrilateral is 16 cm. The perpendiculars drawn to it from its opposite vertices are 2.6 cm and 1.4 cm. Find its area.
a.32cm^2
b.40cm^2
c.26cm^2
d.28cm^2​

Answer 1

Answer:

a. 32cm²

Step-by-step explanation:

diagonal(d) = 16cm

perpendicular 1 (a₁) = 2.6cm

perpendicular 2 (a₂) = 1.4cm

area of quadrilateral = $\frac{1}{2} d(a1 + a2)$

                                  $= (\frac{1}{2}) 16(2.6+1.4)\\= 8 (4)\\= 32cm^{2}$