One of the diagonals of a rhombus is 70% of the other diagonal. What is the ratio of area the rhombus to the square of the length of the larger diagonal ?
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Area of a rhombus = pq/2
Where p and q are the diagonals
if one diagonal = x the other diagonal = 70/100 x = 0.7x
Area of the rhombus = 1/2(x)(0.7x) = 0.35x²
Area of square of side x = x*x = x²
The ratio of area the rhombus to the area of square = 0.35x² : x²
= 7 : 20
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Answer:
Step-by-step explanation:
Area of a rhombus = pq/2
Where p and q are the diagonals
if one diagonal = x the other diagonal = 70/100 x = 0.7x
Area of the rhombus = 1/2(x)(0.7x) = 0.35x²
Area of square of side x = x*x = x²
The ratio of area the rhombus to the area of square = 0.35x² : x²
= 7 : 20
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