One of the diagonals of a rhombus is equal to its sides find the angles of the Rhombus.
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So angles of rhombus are 60, 60, 120 and 120
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ABCD is a rhombus.
⇒AC=BC ........(1)(given)
BC=AB .....(2)(side of rhombus)
From eqns(1) and (2)
AC=BC=AB
⇒△ABC is equilateral triangle.
So, ∠ABC=60
∠BCA=60 ..........(3)
∠CAB=60 ..........(4)
Similarly, in △ADC,AD=DC(sides of a rhombus)
AD=BC
But BC=AC
∴AD=AC
∴AD=DC=AC
∴DAC is an equilateral triangle.
⇒∠CAD=60. ......(5)
⇒∠ADC=60
⇒∠DCA=60 .......(6)
From eqns(3) and (6) we get
∠BCA+∠DCA= 60 + 60 = 120
∴∠C=120
From eqns(4) and (5),
∠CAB+∠CAD=60 +60 =120
∴∠A=120
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