Question

One of the diagonals of a rhombus is thrice as the other. If the sum of the length
the diagonals is 24 cm, then find the area of the rhombus.​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

54

hope this will help you

Answer 2

Answer:

The area of the rhombus is 54cm².

Step-by-step explanation:

Consider the provided information.

It is given that one of the diagonals of a rhombus is thrice as the other.

Let us consider the length of one diagonal is x.

Then the length of another diagonal will be 3x.

The sum of the length of the diagonal is 24cm.

Therefore,

x + 3x = 24

4x = 24

x = 6

The length of one diagonal is 6cm. Then the length of another diagonal will be 3x = 3(6) = 18cm

The area of the rhombus is:

$A=\frac{pq}{2}$

Where, p and q are the diagonals.

Substitute p = 6 and q = 18 in the above formula.

$A=\frac{6\times18}{2}$

$A=\frac{108}{2}$

$A=54$

Hence, the area of the rhombus is 54cm².