Question

- One of the diagonals of
la chombus is 15 cm and
lits area is 150 cm2. The
perimeter is equal to:
​

Answer 1

one diagonal of rhombus =15 cm

area of rhombus =1/2 *15 *other diagnol

so other diagnol = 1/2 *15*x=150

= 10 cm .

diagnals of rhombus bisect each other at right angles . by using Pythagoras theorem, we get

(5)^2 + (7.5)^2 =( one side of rhombus )^2

=9 cm

so the perimeter = 9 * 4 = 36 cm

I hope this will help