Question

one of the diagonals of rhombus is thrice as the other . If the sum of the length of the diagonals is 24cm, then find the area of the rhombus.​

Answer 1

Answer:

54cm^2

Step-by-step explanation:

Let one of the diagonals of rhombus be ‘d1’ cm and the other be d2 cm.

Give d1 = 3 x d2

Also d1 + d2 = 24 cm

⇒ 3d2 + d2 = 24

4d2 = 24

d2 = 24/4

d2=6 cm

d1 = 3 x d2 = 3 x 6

d1 = 18 cm

∴ Area of the rhombus = 1/2 x d1 x d2 sq. units

= 1/2 x 18 x 6 cm2 = 54 cm2

Area of the rhombus = 54 cm2

Answer 2

$\huge\underbrace\mathrm\purple{Answer}$

54cm²

Step-by-step explanation:

Let one of the diagonals of rhombus be ‘d1’ cm and the other be d2 cm.

Give d1 = 3 x d2

Also d1 + d2 = 24 cm

⇒ 3d2 + d2 = 24

4d2 = 24

d2 = 24/4

d2=6 cm

d1 = 3 x d2 = 3 x 6

d1 = 18 cm

∴ Area of the rhombus = 1/2 x d1 x d2 sq. units

= 1/2 x 18 x 6 cm2 = 54 cm2

Area of the rhombus = 54 cm2