Math, asked by sjariwala1700, 11 months ago

ONE OF THE DIAGONALS OF THE RHOMBUS IS 30 CM AND ITS PERIMETER IS 68 . FIND THE LENGTH OF THE OTHER DIAGONAL

Answers

Answered by Mehnaaz03
3

Answer:

Area of rhombus = 1/2 x D1 x D2

Perimeter = 68 = 4 x side

side = 68/4 = 17m

a rhombus can b divided into 4 triangles

in one triangle

hypotenuse^2 = half pf diagonal^2 + half of diagonal2^2

17 x 17 = 15 x 15 + d2^2

1/2d2^2 = 64

D2 = 8 x 2 = 16

diagonal is 16 m

Answered by shivreddy
0

Answer:

this below answer is right

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