Question

One of the digit of a two digit number is four times the other digit. if we interchange the digits, the sum of the new number formed , and the original number is 55. find the original number​

Answer 1

Let the digit in units place be x.

Then, digit in ten's place =3x

So, original number =10(3x)+x=31x

On interchanging the digits, new number =10x+3x=13x

According to the given condition,

31x+13x=88

⇒44x=88

⇒x=2

So, the original number is 31x or 31×2=62.

On the other hand, if we consider the digit in ten's place as x, then the digit in the unit's place will be 3x.

So, original number =10(x)+3x=13x

On interchanging the digits, new number =10(3x)+x=31x

According to the given condition,

13x+31x=88

⇒44x=88

⇒x=2

So, the original number is 13x or 13×2=26.

Here, both answers are correct, as 26+62=88

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