Question

One of the digits of a two digit number is 3 times the other digit.
If you interchange the digits and add the resulting number to the original number,you get 88. what is the number?​

Answer 1

Answer:

The number is 62

Explanation:

let two digits be x and y respectively

So, the two digit number = 10x + y (original number)

Given,

one digit = 3 times the other digit

let x = 3y ---> (1)

On interchanging the digits of the two digit number, we get ☞ 10y + x (resulting number)

According to the question,

Original number + resulting number = 88

=> 10x + y + 10y + x = 88

=> 11x + 11y = 88

Taking 11 common

=> 11(x + y) = 88

=> x + y = 88/11

=> 3y + y = 8 { x = 3y, using (1) }

=> 4y = 8

=> y = 8/4

=> y = 2

Original number = 10x + y

=> 10(3y) + y {∵ x = 3y }

=> 30y + y

=> 31y

=> 31(2) { putting y = 2 }

=> 62